185k views
0 votes
Find g/f and its domain when g(x) = x² - 4x - 5 and f(x) = 4 - 3x.

A. g/f = x² - 4x - 5 / 4 - 3x; domain x ≠ 4/3.
B. g/f = 4 - 3x / x² - 4x - 5; domain x ≠ 4/3.
C. g/f = 4 - 3x / x² - 4x - 5; domain x ≠ -5, 1.
D. g/f = 4 - 3x / x² - 4x - 5; domain x ≠ 5, -1.

User MychaL
by
8.1k points

1 Answer

2 votes

Final answer:

The quotient g/f is (x² - 4x - 5) / (4 - 3x) and the domain is all real numbers except for x ≠ 4/3, making option A the correct answer.

Step-by-step explanation:

The question asks us to find the quotient g/f where g(x) = x² - 4x - 5 and f(x) = 4 - 3x and to determine its domain. First, we form the quotient:

g/f = (x² - 4x - 5) / (4 - 3x)

To find the domain, we need to identify where the denominator is not zero since division by zero is undefined. Setting the denominator equal to zero gives us 4 - 3x = 0, which can be solved to find that x = 4/3. This means the function is undefined at x = 4/3.

Therefore, the correct option is A. g/f is equal to (x² - 4x - 5) / (4 - 3x) and the domain is all real numbers except x ≠ 4/3.

User Samuel Dressel
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories