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If g(x) = ∫√x 8 tdt then, g'(x) =

A. 4√x

B. 4x^(3/2)

C. 2x^(3/2)

D. 4√x + C (with C as the constant of integration)

User ShowFocus
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1 Answer

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Final answer:

The derivative of g(x) = ∫√x 8 tdt is 4√x.

Step-by-step explanation:

In this problem, we are given the function g(x) = ∫√x 8 tdt. We need to find the derivative of g(x), which is denoted as g'(x).

To find the derivative of g(x), we need to use the Fundamental Theorem of Calculus. According to this theorem, the derivative of the integral of a function is equal to the original function.

So, in this case, g'(x) = √x 8, which simplifies to A. 4√x.

User Chengbo
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