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The two non-parallel sides of an isosceles trapezoid are each 7 feet long. The longer of the two bases measures 22 feet long. The sum of the base angles is 140°.

a. Find the length of the diagonal.
b. Find the length of the shorter base.

A) a. 11 feet, b. 15 feet
B) a. 15 feet, b. 11 feet
C) a. 18 feet, b. 15 feet
D) a. 22 feet, b. 7 feet

1 Answer

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Final answer:

The length of the diagonal of the isosceles trapezoid is 15 feet, and the length of the shorter base is 22 feet.

Step-by-step explanation:

To find the length of the diagonal of the isosceles trapezoid, we can use the Pythagorean theorem. Let the length of the shorter base be x. Since the two non-parallel sides are each 7 feet long, the height of the trapezoid is also 7 feet. Using the Pythagorean theorem, we have (7/2)^2 + x^2 = (22/2)^2. Simplifying this equation gives x^2 = (22/2)^2 - (7/2)^2. Solving for x, we find x = 15 feet. Therefore, the length of the diagonal is 15 feet.

For part (b), since the longer base measures 22 feet long, the length of the shorter base is also 22 feet.

User John Zhao
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