Final answer:
The work done by the hoist, lifting a 260 kg rock to a height of 6 m against gravity, is 15,288 joules. Calculated using the formula (W = mgh), where (m) is the mass, (g) is the acceleration due to gravity, and (h) is the height, with (g) assumed as approximately 9.8 m/s².
Step-by-step explanation:
This is asking about the work done when a hoist lifts a rock to a certain height. To calculate this, we use the formula for work done against gravity, which is W = mgh, where m is mass, g is the acceleration due to gravity, and h is the height. For the given scenario where the mass of the rock (m) is 260 kg and the height (h) to which it is lifted is 6 m, we can plug these values into the formula. Assuming g is approximately 9.8 m/s2, the acceleration due to gravity: W = 260 kg × 9.8 m/s2 × 6 m = 15288 J. The work done by the hoist is 15,288 joules (J).