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a honda civic travels in a straight line along a road. its distance x from a stop sign is given as a function of time t by the equation x(t)=αt2−βt3 , where α = 1.40 m/s2 and β = 0.0530 m/s3

User Baralong
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  • Final answer:

The question pertains to the calculation of distance using kinematic equations in physics, which is a high school-level concept. Calculations involve plugging values into the distance equation and establishing relationships between displacement, average velocity, and time.

Step-by-step explanation:

The subject of the question involves calculating the distance traveled by a Honda Civic using the equation of motion x(t)=αt^2−βt^3, where α and β are given constants and represent the rates of acceleration and deceleration. Calculating such a distance involves understanding kinematics, which is a part of physics that deals with the motion of objects without considering the forces that cause the motion. Using the given values α = 1.40 m/s^2 and β = 0.0530 m/s^3, one can find the position of the car at any time 't' by plugging the value of 't' into the equation.

As an example, the equation x = xo + ut explains the connection between displacement, average velocity, and time. In physics, understanding these relationships is crucial in solving problems that involve motion. Moreover, working with velocity-time graphs is essential for visualizing and interpreting different stages of the vehicle's journey, such as acceleration, constant velocity, and deceleration.

User Darren Shewry
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