Final answer:
The final velocity of Jeff Gordon's race car at the end of the 400 m distance is approximately 46.48 m/s, calculated using the kinematic equation v^2 = u^2 + 2as, where u=0, a=2.7 m/s², and s=400 m.
Step-by-step explanation:
To find the final velocity of Jeff Gordon's race car, we need to use the kinematic equation which relates acceleration, initial velocity, distance, and final velocity:
v2 = u2 + 2as
Where v is the final velocity, u is the initial velocity (which is 0 since he starts from rest), a is the acceleration, and s is the distance covered.
Since the initial velocity (u) is 0, the equation simplifies to v2 = 2as. Plugging in the values:
v2 = 2 * 2.7 m/s2 * 400 m
v2 = 2160 m2/s2
v = √2160 m2/s2
v ≈ 46.48 m/s
Therefore, the final velocity at the end of the 400 m distance is approximately 46.48 m/s. This is not one of the provided options, implying there might be a typo in the answer choices.