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What is an equation of the line that passes through the points (-8, -4) and (-6, -5)?

a) y = 2x - 6
b) y = -x - 4
c) y = x - 4
d) y = -2x - 4

User Harrybvp
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1 Answer

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Final answer:

The equation of the line that passes through the points (-8, -4) and (-6, -5) is y = (-1/2)x - 8.

Step-by-step explanation:

The equation of the line that passes through the points (-8, -4) and (-6, -5) can be found using the slope-intercept form, which is given by y = mx + b, where m represents the slope and b represents the y-intercept. To find the slope, we use the formula m = (y2 - y1) / (x2 - x1). Plugging in the coordinates (-8, -4) and (-6, -5), we get m = (-5 - (-4)) / (-6 - (-8)) = (-5 + 4) / (-6 + 8) = -1 / 2. Now that we have the slope, we can choose one of the points and the slope to write the equation. Using the point (-8, -4), we get y = (-1/2)x + b. Plugging in the x- and y-coordinates of the point, we can solve for b: -4 = (-1/2)(-8) + b -> -4 = 4 + b -> b = -8. Therefore, the equation of the line is y = (-1/2)x - 8. The correct answer is none of the options given in the question, so the answer is not provided.

User Triana
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