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ABCD is a trapezoid with bases AB and DC. We know that angle C = 60^° and angle D = 45^°. If AB = 5 - 2√3 and BC = 4, what is DC?

A) 2√3
B) 5 - 2√3
C) 6 - 2√3
D) 2√6

1 Answer

3 votes

Final answer:

Using the properties of 30-60-90 and 45-45-90 triangles within a trapezoid, we calculate that the length of DC should be 3 + 2√3. There seems to be a discrepancy as none of the provided answer choices match the calculated value.

Step-by-step explanation:

Since ABCD is a trapezoid with bases AB and DC, and given angles C = 60 degrees and D = 45 degrees, to find DC, we can use the properties of a trapezoid and the given side and angle measures. We can represent the trapezoid as two right triangles and a rectangle combined. The triangle at base BC will have sides BC and a part of DC, let us call it x. Applying the Pythagorean theorem, we could find x and subsequently DC.

Angle C of 60 degrees in triangle BCD suggests that triangle BCD is a 30-60-90 triangle, where sides are in a ratio of 1:√3:2. Since BC is given as 4, and it corresponds to the √3 part of the ratio, and the smaller part (opposite the 30 degrees angle) would be half of this, which is 2, and the hypotenuse (CD) would be double of this, which is 8. Now, we need to find the part of DC that is subtracted due to the trapezoid not being symmetrical. For this, we can use the 45-45-90 triangle at base AD. If AD is 5 - 2√3, then the horizontal leg that belongs to DC (x) is the same length because the sides opposite the 45-degree angles are equal.

Subtracting the x (5 - 2√3) from the total of DC (8), we get DC = 3 + 2√3, which is not one of the provided options. There seems to be an error in the provided options or the initial given values, as none of the options match the calculated value for DC.

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