The power delivered to the 5-ohm resistor in the circuit can be found using the formula P = I^2 R. By calculating the current and resistance values, we can substitute them into the formula to get the power. In this case, the power delivered to the 5-ohm resistor is 500 W.
In the circuit shown, the power delivered to the 5-ohm resistor can be calculated using the formula P = I^2 R, where P is the power, I is the current, and R is the resistance.
To find the current, we can use Ohm's Law: V = I R, where V is the voltage and R is the resistance.
The voltage across the 5-ohm resistor is the same as the total voltage in the circuit, which is 50.00 V. So, we have V = 50.00 V and R = 5 ohms.
Rearranging the equation, we have I = V / R, which gives us I = 50.00 V / 5 ohms = 10 A.
Now, we can substitute the values of I and R into the power formula: P = (10 A)^2 5 ohms = 100 5 = 500 W.
Therefore, the power delivered to the 5-ohm resistor in the circuit shown is 500 W.
question:
17.63 The voltage across the 5-ohm resistor in the circuit
shown is
a) 1.0
b) 2.5
c) 3.0
d) 5.83
17.64 The power delivered to the 5-ohm
resistor is
a) 1.5
b) 2.15
c) 2.85
d) 3.2
15 V3Ω502100 W802 W12 V50Lw6V20 Ω