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A 1500 kg car moving 30.0 m/s crashes into a wall and stops in 0.5 s. What is the change in momentum of the car?

a) 30 m/s
b) 1500 kg m/s
c) 45,000 kg m/s
d) 750 kg m/s

1 Answer

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Final answer:

The change in momentum of the car is the magnitude of the initial momentum, which is 45000 kg·m/s, calculated by multiplying the car's mass (1500 kg) by its initial velocity (30.0 m/s).

Step-by-step explanation:

The question asks for the change in momentum of a car after it crashes into a wall and comes to a stop. Momentum (p) is calculated as the product of an object's mass (m) and its velocity (v), given by the formula p = m × v. To find the change in momentum (Δp), we subtract the final momentum from the initial momentum.

In this case, since the car comes to a stop, its final momentum is 0 kg·m/s. The initial momentum of the car can be calculated as the product of its mass (1500 kg) and its velocity (30.0 m/s), which equals 45000 kg·m/s.

Since the car's final momentum is 0, the change in momentum is equal to the negative of the initial momentum, which is -45000 kg·m/s (the negative sign indicates a reduction in momentum). However, since the question appears to ask for the magnitude of the change, we can drop the sign and the answer is 45000 kg·m/s.

User John Rice
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