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What is the change in momentum of a basketball that exerts 54.1 N of force on a wall for 7.5 seconds? kgm/s

a) 405.75 kgm/s
b) 405.75 Ns
c) 405.75 kgm/s²
d) 405.75 N

1 Answer

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Final answer:

The change in momentum of the basketball is 405.75 Ns (Newton-seconds), calculated using the impulse-momentum theorem by multiplying the force (54.1 N) by the time (7.5 seconds).

Step-by-step explanation:

The change in momentum of a basketball that exerts a force of 54.1 N on a wall for 7.5 seconds can be calculated using the impulse-momentum theorem, which states that impulse equals the change in momentum (Impulse = Force x Time = Change in Momentum). To find the change in momentum, we multiply the force by the time period during which the force was applied:

Change in Momentum = Force x Time

= 54.1 N x 7.5 s

= 405.75 Ns (Newton-seconds)

Hence, the correct answer is b) 405.75 Ns, which represents the unit of impulse and also the change in momentum in the International System of Units (SI).

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