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Write an equation of the line that passes through (-5, -2) and is parallel to (y = 2/3x + 1).

a) (y = 2/3x - 13/3)
b) (y = 3/2x - 1\)
c) (y = 2/3x - 1\)
d) (y = 2/3x - 2/3)

User Jonathan M
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1 Answer

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Final answer:

To find the equation of a line parallel to y = (2/3)x + 1 and passing through the point (-5, -2), we can use the point-slope form of a line.

Step-by-step explanation:

To find the equation of a line parallel to y = (2/3)x + 1 and passing through the point (-5, -2), we need to use the fact that parallel lines have the same slope. The given line has a slope of 2/3, so the parallel line will also have a slope of 2/3. Using the point-slope form of a line, the equation of the parallel line can be written as:



y - y1 = m(x - x1)



Substituting the coordinates of the given point and the slope, we get:



y + 2 = (2/3)(x + 5)



Simplifying this equation gives us the answer:



y = (2/3)x - 13/3

User Pablo Montilla
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