Question

May I get help, the last tutor never responded

Answer 1

`\begin{gathered} Let\text{ P(x) represents the probability that }her\text{ family has a ri}sk\text{ of heart attack} \\ P(x)=70\text{\%=}(70)/(100)=0.7 \end{gathered}`
`\begin{gathered} \text{Let P(y) represent the probability of the reliability of the }stress\text{ test} \\ P(y)=67\text{\%=}(67)/(100)=0.67 \end{gathered}`
`\begin{gathered} Let\text{ P(x') be the event that her family will NOT have a risk of heart attack} \\ P(x^(\prime))=1-P(x) \\ P(x^(\prime))=1-0.7 \\ P(x^(\prime))=0.3 \end{gathered}`
`\text{ity that Erin will not have a heart attack and the test predicts that she will is:}`