Question

A child weighs 250 N and is carrying a backpack that weighs 17 N. The child walks 8.8 meters across the hallway to class.

How much total work does the child do?
OOJ
2,349.6 J
149.6 J
2,200 J

Answer 1

The total work done by the child is 2346.4 J.

Step-by-step explanation:

To calculate the total work done by the child, we need to consider the work done against gravity and the work done against friction. The work done against gravity is given by the formula work = force x distance x cos(theta), where theta is the angle between the force and the displacement.

In this case, the force due to gravity is the weight of the child and the backpack combined, which is (250 N + 17 N) = 267 N. The displacement is the distance the child walks, which is 8.8 meters. The angle between the force and displacement is 0 degrees, since the force is parallel to the displacement.

So the work done against gravity is work = 267 N x 8.8 m x cos(0 degrees) = 2346.4 J. There is no work done against friction mentioned in the question, so we can assume it is negligible.

Therefore, the total work done by the child is 2346.4 J.