step 1
Find the slope od the line
we need two points
we have
(0,-3) and (4,1)
m=(1-(-3))/(4-0)
m=(1+3)/4
m=1
step 2
Find the equation of the line in slope intercept form
y=mx+b
where
m is the slope
b is the y-intercept
In this problem
we have
m=1
b=-3 -------> is given (point (0,-3)
substitute
y=x-3
or
y=(1)x+ (-3)
Part 2
step 1
Find the slope
m=(-9+20)/(1+10)
m=11/11
m=1
step 2
Find the equation of the line in point slope form
y-y1=m(x-x1)
we have
m=1
(x1,y1)=(-10,-20)
substitute
y+20=(1)(x+10)
or
y-(-20)=(1)(x-(-10))