Question

These exercises use the radioactive decay model. The half-life of cesium- 137 is 30 years. Suppose we have a 10-g sample. Find a function m(t) = m02⁻ᵗ/ʰ that models the mass remaining after t years. m(t) =

Answer 1

The function m(t) = m0 * 2^(-t/h) represents the remaining mass of a radioactive substance after t years, where m0 is the initial mass and h is the half-life of the substance. In this case, the half-life of cesium-137 is 30 years and the initial mass is 10 g. So, the function m(t) = 10 * 2^(-t/30) models the mass remaining after t years.

Step-by-step explanation:

The function m(t) = m0 * 2^(-t/h) represents the remaining mass of a radioactive substance after t years, where m0 is the initial mass and h is the half-life of the substance. In this case, the half-life of cesium-137 is 30 years and the initial mass is 10 g. So, the function m(t) = 10 * 2^(-t/30) models the mass remaining after t years.