Question

2. *** (204)+ 44) I V9+1 4. 3. Evaluate a3 – 5g + V34 - 30* if a = 2 and g = 3 ** Evaluate 9(2x + 7) + 8 + 777 + -3 2

Answer 1

For the part 1: the answer is 117, because:

`((9+4)+((20)/(2))^2)+2^2`

we first need to solve what is in the parenthesis:

`(13+10^2)+2^2`

know we simplify the exponents:

`(13+100)+4`

then we make the sum in the parenthesis:

`113+4=117`

For the part 2: the answer is 33, because:

`((20)/(4))^2+\sqrt[]{((14+8)+42)}`

we solve first what is in the parenthesis that have no more parenthesis inside them:

`5^2+\sqrt[]{(22+42)}`

then we simplify the exponent and make the addition inside the square root:

`25+\sqrt[]{64}=25+8=33`

For the part 3: the answer will be -5, because:

`a^3-5g+\sqrt[]{34-30}*(\frac{\sqrt[]{g+1}}{2})`

if a=2 ang g=3, we have that

`=2^3-5(3)+\sqrt[]{34-30}*(\frac{\sqrt[]{4}}{2})`

we will first solve the exponents and the square root:

`=8-5(3)+\sqrt[]{4}*(\frac{\sqrt[]{4}}{2})=8-5(3)+2`

we now solve the multiplication:

`=8-15+2`

now, we make thee addition and the substraction:

`=10-15=-5`

For the part 4: the answer will be 26, because:

`9(2x+7)+8+\sqrt[]{77+4}`

when x=-3, the expression will be:

`9(2(-3)+7)+8+\sqrt[]{77+4}`

we will first solve what is in the square root:

`9(2(-3)+7)+8+\sqrt[]{81}=9(2(-3)+7)+8+9`

then we will solve the multiplication:

`=9(-6+7)+8+9`

now we solve what's in the parenthesis:

`=9(1)+8+9=9+8+9=26`