Question

How many moles are in 3.24 x 1020 particles of lead? (show work plz)

Answer 1

0.000538 mol Pb

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

3.24 × 10²⁰ particles Pb (lead)

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

1. Set up:
   `\displaystyle 3.24 \cdot 10^(20) \ particles \ Pb((1 \ mol \ Pb)/(6.022 \cdot 10^(23) \ particles \ Pb))`
2. Multiply/Divide:
   `\displaystyle 0.000538 \ mol \ Pb`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

Our final answer is in 3 sig figs, no need to round.