Question

calculate the concentration of cl- in a solution made by mixing 41.4 ml of 1.03 m nacl with 66.2 ml of 0.818 m cacl2 and diluting to 300.0 ml.

Answer 1

To calculate the concentration of Cl- in the solution, you need to calculate the number of moles of Cl- and then divide it by the volume of the solution. The concentration of Cl- in the solution is 0.32233 M.

Step-by-step explanation:

To calculate the concentration of Cl- in the solution, we need to calculate the number of moles of Cl- and then divide it by the volume of the solution.

The number of moles of Cl- in NaCl is obtained by multiplying the volume of NaCl solution (41.4 mL = 0.0414 L) with the molarity of NaCl (1.03 M). So, moles of Cl- in NaCl = 0.0414 L × 1.03 M = 0.042622 mol.

The number of moles of Cl- in CaCl2 is obtained by multiplying the volume of CaCl2 solution (66.2 mL = 0.0662 L) with the molarity of CaCl2 (0.818 M). So, moles of Cl- in CaCl2 = 0.0662 L × 0.818 M = 0.054076 mol.

The total moles of Cl- in the solution is the sum of moles of Cl- from NaCl and CaCl2. So, total moles of Cl- = 0.042622 mol + 0.054076 mol = 0.096698 mol.

The volume of the final solution is 300.0 mL = 0.3 L.

Now, we can calculate the concentration of Cl- in the solution by dividing the total moles of Cl- by the volume of the solution:

Concentration of Cl- = total moles of Cl- / volume of solution = 0.096698 mol / 0.3 L = 0.32233 M.