Question

2 ml of 5 m hydrochloric acid (hcl) is titrated with sodium hydroxide (naoh). how many mmols of sodium hydroxide are consumed in this reaction?

Answer 1

In this reaction, 2 mL of 5 M HCl is reacted with NaOH. The mole ratio of HCl to NaOH is 1:1, so 0.01 mol of NaOH will be consumed.

Step-by-step explanation:

In this titration reaction, 2 mL of 5 M hydrochloric acid (HCl) is being reacted with sodium hydroxide (NaOH). The balanced chemical equation for this reaction is:

HCl + NaOH → NaCl + H₂O

From the balanced equation, we can see that the mole ratio of HCl to NaOH is 1:1. Therefore, if 2 mL of 5 M HCl is used, we can calculate the number of moles of HCl:

Moles of HCl = Volume (L) x Concentration (M)

Moles of HCl = (2 mL / 1000 mL/L) x 5 M = 0.01 mol

Since the mole ratio of HCl to NaOH is 1:1, 0.01 mol of NaOH will also be consumed in this reaction.