Final answer:
Both matrices A and B have non-zero determinants of 2, meaning they both technically have inverses.Assuming matrix A was intended to be the one with an inverse, its inverse can be found using a method that involves its adjugate and determinant.
Step-by-step explanation:
In mathematics, particularly in linear algebra, the inverse of a matrix exists only if the determinant of the matrix is not zero. The determinant is a special value that can be calculated from the elements of a square matrix. We will calculate the determinants of matrices A and B to determine which one has an inverse.
For matrix A:
A =
\begin{bmatrix}
1 & 4 & 1 \\
0 & 2 & 0 \\
1 & 0 & 1
\end{bmatrix}
The determinant of matrix A can be calculated as follows:
det(A) = 1(2*1 - 0*0) - 4(0*1 - 0*1) + 1(0*0 - 2*1) = 2.
Since the determinant of matrix A is non-zero, it has an inverse.
For matrix B:
B =
\begin{bmatrix}
1 & 4 & 0 \\
0 & 2 & 0 \\
-3 & 0 & 1
\end{bmatrix}
The determinant of matrix B is:
det(B) = 1(2*1 - 0*0) - 4(0*1 - 0*(-3)) + 0(0*0 - 2*(-3)) = 2 - 0 + 0 = 2.
Both matrices A and B have non-zero determinants, which means they both have inverses.