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what is the diffraction angle in degrees for a setup using a 3,660 angstrom slit with a minima of order 26 and a wavelength of 12 nm? round to 2 decimals.

User Hito
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Final answer:

The diffraction angle for a setup using a 3,660 Ångstrom slit with a minima of order 26 and a wavelength of 12 nm is approximately 80.87 degrees.

Step-by-step explanation:

To find the diffraction angle for a setup using a 3,660 Ångstrom slit, we can use the formula:

sinθ = m * λ / w

where θ is the diffraction angle, m is the order of the minima, λ is the wavelength of light, and w is the width of the slit.

Plugging in the given values: m = 26, λ = 12 nm = 12000 Ångstroms, and w = 3660 Ångstroms, we get:

sinθ = 26 * 12000 / 3660

solving for θ, we find:

θ = arcsin(26 * 12000 / 3660)

Calculating this value, we find that the diffraction angle θ is approximately 80.87 degrees.

User Pravy
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