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consider a ball that rolls across a table with a speed of 1 meters per second. the table is 1 meter above the floor where does the ball hit the floor?

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Final answer:

The ball hits the floor instantly as it is dropped from a height of 1 meter above the floor.

Step-by-step explanation:

In order to find where the ball hits the floor, we can use the equation of motion for a freely falling object:

h = (1/2)gt^2 + V_i*t + h_i

where h is the height, g is the acceleration due to gravity, t is the time, V_i is the initial velocity, and h_i is the initial height.

Since the ball is dropped, the initial velocity is 0 m/s and the initial height is 1 meter above the floor. Plugging in the given values, we get:

1 = (1/2)(9.8)(t^2) + (0)(t) + 1

Simplifying the equation, we have:

t^2 = 0

This means that the ball hits the floor instantly as it is dropped from a height of 1 meter above the floor.

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