Question

a titration is performed on an unknown monoprotic acid. it requires 35.22 ml of 0.100 m naoh to titrate 0.242 g of the acid. what is the molar mass of this acid?

Answer 1

The molar mass of the unknown monoprotic acid is 68.8 g/mol.

Step-by-step explanation:

To find the molar mass of the unknown monoprotic acid, we can use the equation:

Moles of acid = Moles of NaOH

First, we need to calculate the number of moles of NaOH used in the titration:

Moles of NaOH = (Volume of NaOH) x (Molarity of NaOH)

Moles of NaOH = (35.22 mL) x (0.100 M)

= 0.003522 moles

Since the acid and NaOH reacted in a 1:1 ratio, the moles of acid is also 0.003522 moles.

To calculate the molar mass of the acid, we can use the formula:

Molar mass = (Mass of acid) / (Moles of acid)

Molar mass = 0.242 g / 0.003522 moles

= 68.8 g/mol