Question

for the position of a particle moving along the x-axis is given by . what is the acceleration of the particle at the point where the velocity is first equal to 0 ?

Answer 1

The acceleration of the particle at t = 2.0 s and t = 5.0 s is -0.03125 m/s² and -0.008 m/s², respectively.

Step-by-step explanation:

The acceleration of a particle can be determined by taking the derivative of its velocity function.

In this case, the velocity function is v(t) = A + Bt⁻¹, where A = 2 m/s and B = 0.25 m.

To find the acceleration at t = 2.0 s and t = 5.0 s, we differentiate the velocity function with respect to time.

The acceleration is given by a(t) = -Bt⁻².

Substituting the respective values of t, we get a(2.0) = -0.03125 m/s² and a(5.0) = -0.008 m/s² for t = 2.0 s and t = 5.0 s, respectively.