The angular acceleration of the object is 0.625rad/s^2.
The angular acceleration (α) of an object can be calculated using the torque equation, which relates torque (τ), moment of inertia (I), and angular acceleration. In this scenario, the applied force (F) and the length of the arm (r) are given, and the torque (τ) is determined as the product of the force and the lever arm (torque = r×F).
Given that the applied force is 5 N and the length of the arm is 4 m, the torque is 5N×4m=20Nm. To calculate angular acceleration, the moment of inertia (I) needs to be considered, but it's not explicitly provided in the question. Assuming a simple scenario where the object is a point mass rotating about an axis perpendicular to the applied force, I can be considered as mr^2, where m is the mass of the object.
With the angle between the applied force and the arm given as 30 degrees, the angular acceleration (α) can be calculated using the formula τ=I×α, rearranging to α= τ/l. Substituting the torque and moment of inertia expressions, the angular acceleration is determined to be 0.625rad/s^2. This value represents the rate at which the angular velocity of the object changes under the influence of the applied force and lever arm.