Question

suppose that the bit pattern 0x08000000 is placed into the instruction register (ir). 2.1. (5 points) what mips instruction will be executed?

Answer 1

The MIPS instruction that will be executed is J 0x00000000.

Step-by-step explanation:

The bit pattern 0x08000000 is a hexadecimal representation of a 32-bit value in memory. In the MIPS assembly language, the instruction register (IR) holds the current instruction being executed by the processor.

The MIPS instruction set architecture uses a 32-bit format, where the first 6 bits (bits 31-26) represent the opcode or instruction category. In this case, the opcode from the bit pattern 0x08000000 is 000010, which corresponds to the J (Jump) instruction category.

The remaining 26 bits (bits 25-0) specify the address to jump to, which in this case is 0x00000000. Therefore, the J instruction that will be executed is J 0x00000000, which directs the processor to jump to the address 0x00000000.