Question

(a) if 26 ml of a 0.17 m hcl solution was used as a titrant to reach the equivalence point, what was the concentration of lithium hydroxide in the initial solution?

Answer 1

To find the concentration of the lithium hydroxide (LiOH) solution, we need to use the concept of titration. In this case, 26 mL of a 0.17 M HCl solution was used as the titrant and reached the equivalence point. The concentration of the LiOH solution was found to be 0.170 M.

Step-by-step explanation:

In titration, a known solution (titrant) is used to react with an unknown solution (analyte) until the equivalence point is reached. At the equivalence point, moles of titrant are equal to moles of analyte.

In this case, 26 mL of a 0.17 M HCl solution was used as the titrant and reached the equivalence point. Since HCl reacts with LiOH according to the balanced chemical equation HCl + LiOH --> LiCl + H2O, we can set up a mole ratio to relate the concentration of HCl to the concentration of LiOH.

Using the mole ratio of 1:1 between HCl and LiOH, we can calculate the concentration of LiOH. We know that moles of HCl = concentration of HCl * volume of HCl solution, so:

moles of HCl = 0.17 M * 0.026 L

= 0.00442 mol HCl

Since moles of HCl = moles of LiOH, the concentration of LiOH is:

concentration of LiOH = moles of LiOH / volume of LiOH solution

= 0.00442 mol / 0.026 L

= 0.170 M.