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The two-way table shows the number of sport utility vehicles with certain features for sale at the car lot.What is the probability that a randomly selected car with no-4wheel drive has third-row seats?

User Tqbf
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The probability that a randomly selected car with no 4-wheel drive has third row seats is 0.3

How to determine the probability value

Let:

A represent A car with no 4-wheel drive

B represent A car that has third row seats

The probability that a randomly selected car with no 4-wheel drive has third row seats is represented as:

P(B | A) = P(B n A)/P(A)

From the 2-way table, we have the following parameters:

A n B = 12

A = 40

So, the probability is:

P(B | A) = 12/40

P(B | A) = 0.3

Hence, the probability that a randomly selected car with no 4-wheel drive has third row seats is 0.3

Question

The two-way table shows the number of sport utility vehicles with certain features for sale at the car lot.What is the probability that a randomly selected car with no-4wheel drive has third-row seats?

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The two-way table shows the number of sport utility vehicles with certain features-example-1
User Noneno
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