The probability that a randomly selected car with no 4-wheel drive has third row seats is 0.3
How to determine the probability value
Let:
A represent A car with no 4-wheel drive
B represent A car that has third row seats
The probability that a randomly selected car with no 4-wheel drive has third row seats is represented as:
P(B | A) = P(B n A)/P(A)
From the 2-way table, we have the following parameters:
A n B = 12
A = 40
So, the probability is:
P(B | A) = 12/40
P(B | A) = 0.3
Hence, the probability that a randomly selected car with no 4-wheel drive has third row seats is 0.3
Question
The two-way table shows the number of sport utility vehicles with certain features for sale at the car lot.What is the probability that a randomly selected car with no-4wheel drive has third-row seats?
See attachment