Final answer:
The first 4 terms of the sequence A(n) = 3n + 2 are 5, 8, 11, and 14.
Step-by-step explanation:
To find the first 4 terms of the sequence given by A(n) = 3n + 2, we need to substitute the first four natural numbers for n in the formula.
For n = 1: A(1) = 3(1) + 2
= 3 + 2
= 5.
For n = 2: A(2) = 3(2) + 2
= 6 + 2
= 8.
For n = 3: A(3) = 3(3) + 2
= 9 + 2
= 11.
For n = 4: A(4) = 3(4) + 2
= 12 + 2
= 14.
Thus, the first four terms of the sequence are 5, 8, 11, and 14.