Question

The projectile launcher shown below will give the object on the right an initial horizontal speed of 14.9 m/s. While the other object will be dropped with no initial speed. The objects are initially 113 cm above the ground and separated by 142 cm. What will be the difference in the landing locations of the two objects?

a) 1.13 meters
b) 1.42 meters
c) 2.55 meters
d) 2.84 meters

Answer 1

The difference in the landing locations of the two objects will be 14.2 meters.

The difference in the landing locations of the two objects can be calculated using the equations of projectile motion.

For the object thrown horizontally with an initial speed of 14.9 m/s, the horizontal distance it travels can be found using the equation: Distance = Speed x Time

Since the object is dropped, it does not have an initial horizontal speed, so its horizontal distance will be 0.

Therefore, the difference in the landing locations of the two objects would be equal to the horizontal distance traveled by the horizontally thrown object, which is 14.2 meters (rounded to two decimal places).