Question

Evaluate the indefinite integral. ſt-513dt 125t + c o -50% - 70,2 - 1250+ c O 312 - 30t + 75 +6 04 - 157° + 75t? - 125+ + C

Answer 1

The initial expression is:

`\int (t-5)^3\text{ dt}`

First we can expant cube so:

`\int t^3-15t^2+75t-125`

and now we can integrate so:

`(t^4)/(4)-5t^3+(75t^2)/(2)-125t+C`

So is option B