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john wants to organize 8 different books (3 math books, 3 history books and 2 novels). if no two math books are next to each other, how many arrangements are possible?

User Mikkel Rev
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Final answer:

To find the number of arrangements possible for the 8 different books, consider the total number of arrangements without any restrictions using the formula for permutations. Then, account for the restriction that no two math books can be next to each other by calculating the number of arrangements of the math books separately.we can multiply the total number of arrangements by the number of arrangements of the math books: 40320 * 6 = 241920.

Step-by-step explanation:

To find the number of arrangements possible for the 8 different books, we can first consider the total number of arrangements without any restrictions. This can be calculated using the formula for permutations, which is n!, where n is the number of objects. In this case, we have 8 books, so the total number of arrangements is 8! = 40320.

Next, we need to consider the restriction that no two math books can be next to each other. We can treat the 3 math books as a single object to calculate the number of arrangements. Since we have 3 math books, the number of arrangements of the math books themselves is 3! = 6.

So, to find the number of arrangements of the 8 books with the restriction, we can multiply the total number of arrangements by the number of arrangements of the math books: 40320 * 6 = 241920.

User Mateostabio
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