Question

what is the concentration of chloride ions in a solution obtained by mixing 170. ml of 0.150 m potassium chloride(aq) with 300. ml of 0.490 m barium chloride(aq). g

Answer 1

The concentration of chloride ions in the solution obtained by mixing the two solutions is 0.380 M.

Step-by-step explanation:

To calculate the concentration of chloride ions in the solution, we first need to find the moles of chloride ions present in each solution.

For the potassium chloride solution, we can use the formula n = CV, where n is the number of moles, C is the concentration, and V is the volume.

Plugging in the values, we get

n = (0.150 M) x (0.170 L)

= 0.0255 mol.

Similarly, for the barium chloride solution, we have

n = (0.490 M) x (0.300 L)

= 0.147 mol.

Finally, to find the total concentration of chloride ions, we add the moles from both solutions and divide by the final volume (0.170 L + 0.300 L = 0.470 L).

So, the concentration of chloride ions in the solution is

(0.0255 mol + 0.147 mol) / 0.470 L = 0.380 M.