Final answer:
To prepare a 500 mL solution with a concentration of 2.00 M, 1666.00 grams of KL are needed.
Step-by-step explanation:
To calculate the grams of KL needed to prepare a 500 mL solution that is 2.00 M, we can use the formula:
moles = molarity × volume (in liters)
First, we convert the volume from mL to L:
500 mL = 0.500 L
Next, we substitute the values into the formula:
moles = 2.00 M × 0.500 L
= 1.00 mol
Finally, we can calculate the grams of KL using the molar mass of KL:
grams = moles × molar mass
grams = 1.00 mol × 1666.00 g/mol '
= 1666.00 g
Therefore, 1666.00 grams of KL are needed to prepare the 500 mL solution with a concentration of 2.00 M.