Final answer:
To prove the first part of the Upper and Lower Bounds Theorem, we need to show that the polynomial P(x) has a lower bound and an upper bound. We are given that P(x) can be divided by (x-b) with a remainder r, where r is greater than or equal to 0. This means that P(x) is decreasing as x approaches infinity, as the remainder r is nonnegative.
Step-by-step explanation:
To prove the first part of the Upper and Lower Bounds Theorem, we need to show that the polynomial P(x) has a lower bound and an upper bound. We are given that P(x) can be divided by (x-b) with a remainder r, where r is greater than or equal to 0. This means that P(x) is decreasing as x approaches infinity, as the remainder r is nonnegative. We also know that all the coefficients in Q(x) are nonnegative, so the polynomial Q(x) is also nonnegative. Therefore, the polynomial P(x) has a lower bound of b and no upper bound.