Question

What is the impulse of a constant force of 50 newtons applied for 0.6 seconds

Answer 1

30 kg·
`(m)/(s)`

Step-by-step explanation:

Impulse is equal to the average force multiplied by the elapsed time, or

J=
`F_(av)`Δt

Your average force
`F_(av)` is 50 newtons because it was a constant force. Your elapsed time Δt was 0.6 seconds.

Multiply these values and you get an impulse of 30 kg·
`(m)/(s)`