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Coupling Glu -> Gln condensation with hydrolysis of ATP is strongly energetically favoured. What is the result?

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Final answer:

The coupling of glucose phosphorylation with ATP hydrolysis is energetically favorable, resulting in a spontaneous and thermodynamically favored reaction with an overall negative free energy change.

Step-by-step explanation:

When coupling the condensation reaction of glucose phosphorylation with the hydrolysis of ATP, the net result is strongly energetically favored. This is because the ATP hydrolysis is an exergonic reaction; it releases a significant amount of free energy (approximately 7 Kcal/mole under standard conditions). This energy release is then used to drive the endergonic reaction of glucose phosphorylation, which under standard conditions would require an input of energy (+3 Kcal/mole).

By coupling these reactions, the overall free energy change (ΔG°) for the process is negative, totaling approximately -4 Kcal/mole. This means that the reaction will proceed spontaneously and is thermodynamically favorable. In biological systems, this principle is important as it allows for reactions that require energy to be driven forward by the energy released from ATP hydrolysis, a process known as energy coupling.

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