Question

What is the molarity of ammonium ions in 42 ml of solution containing 22 grams of ammonium phosphate

Answer 1

The molarity of ammonium ions (NH4+) in a 42 ml solution of ammonium phosphate with a mass of 22 grams is calculated to be 10.536 M.

Step-by-step explanation:

To calculate the molarity of ammonium ions (NH4+) in a solution containing ammonium phosphate ((NH4)3PO4), we need to follow these steps:

1. Determine the molar mass of ammonium phosphate.
2. Calculate the number of moles of ammonium phosphate in the given mass (22 grams).
3. Since each formula unit of ammonium phosphate produces three ammonium ions upon dissolution, multiply the number of moles of ammonium phosphate by three to get the number of moles of ammonium ions.
4. Divide the number of moles of ammonium ions by the volume of the solution in liters to calculate the molarity.

Molar mass of (NH4)3PO4 = (3 × 14.007) + (3 × 4 × 1.008) + 30.974 + (4 × 15.999) = 149.086 g/mol

Number of moles of (NH4)3PO4 = 22 g / 149.086 g/mol = 0.1475 moles

Number of moles of NH4+ = 0.1475 moles × 3 = 0.4425 moles

Volume in liters = 42 mL / 1000 = 0.042 L

Molarity of NH4+ = 0.4425 moles / 0.042 L = 10.536 M