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at this time, what was the spacecraft's kinetic energy relative to the earth? express your answer in joules.

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The spacecraft's kinetic energy relative to the earth is 3.49 x 10¹¹ J.

How to calculate the kinetic energy of the spacecraft?

The spacecraft's kinetic energy relative to the earth is calculated by applying the following formula as shown below;

K.E = ¹/₂mv²

where;

  • m is the mass of the spacecraft
  • v is the velocity of the spacecraft

The given parameters include;

mass of the spacecraft, m = 629 kg

velocity of the spacecraft, v = 120,000 km/h = 33,333.3 m/s

The spacecraft's kinetic energy relative to the earth is calculated as;

K.E = ¹/₂ x 629 x (33,333.3)²

K.E = 3.49 x 10¹¹ J

The complete question is below:

Ten days after it was launched toward Mars in December 1998, the Mars Climate Orbiter spacecraft (mass 629 kg) was 2.87×106km from the earth and traveling at 1.20×104km/h relative to the earth. At this time, what were the following. (a) the spacecraft's kinetic energy relative to the earth J

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