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iron has a density of 7870 kg/m3. what is the weight of an iron rod that has a diameter of 12 cm and a length of 50 cm?

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Final answer:

To find the weight of the iron rod, calculate the volume of the rod by using the formula V = πr²h, where r is the radius and h is the height (or length) of the cylinder. Then, multiply the volume by the density of iron to find the weight.

Step-by-step explanation:

To find the weight of the iron rod, we need to calculate the volume of the rod and then multiply it by the density of iron.

The volume of a cylinder is given by the formula V = πr²h, where r is the radius and h is the height (or length) of the cylinder.

In this case, the diameter of the rod is 12 cm, so the radius is half of that, which is 6 cm or 0.06 m.

The height (length) of the rod is given as 50 cm, so it remains as 0.50 m.

Using the formula, we can calculate the volume:

V = π(0.06 m)²(0.50 m)

= 0.0036π m³.

The density of iron is 7870 kg/m³.

Now we can find the weight of the rod by multiplying the volume by the density:

Weight = 0.0036π m³ * 7870 kg/m³

= 22.558 kg.

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