The percentage of the ball's energy dissipated is 20%.
How to calculate the percentage of the ball's energy dissipated?
The percentage of the ball's energy dissipated is calculated as follows;
change in potential energy = mgh₂ - mgh₁
change in potential energy = mg(h₂ - h₁)
change in potential energy = mg(0.8h₁ - h₁)
change in potential energy = - mg(0.2h₁)
The percentage of the ball's energy dissipated is calculated as;
percentage of energy dissipated = change in potential energy / initial potential energy x 100%
percentage of energy dissipated = (0.2mgh₁) / mgh₁) x 100
percentage of energy dissipated = 20%
The complete question is below:
what percent of the ball's energy is dissipated while the ball is in contact with the floor if h 2 is equal to 4/5 h 1 ?