Question

39.a projectile is launched vertically upward from groundlevel with an initial velocity of 112 ft/s.(a) find the velocity att

Answer 1

To find the velocity at the maximum height, use the equation Vf = Vi + at, where Vf is the final velocity, Vi is the initial velocity, a is the acceleration due to gravity, and t is the time taken to reach the maximum height. Substitute the values and solve for t to find the time taken to reach the maximum height. The velocity at the maximum height is 0 ft/s.

Step-by-step explanation:

To find the velocity at the maximum height, we can use the following equation:

Vf = Vi + at

Where:

• Vf is the final velocity
• Vi is the initial velocity
• a is the acceleration due to gravity
• t is the time taken to reach the maximum height

Since the projectile is launched vertically upward, the initial velocity is positive and the acceleration due to gravity is negative.

In this case, the initial velocity is 112 ft/s and the acceleration due to gravity is -32 ft/s^2. The time taken to reach the maximum height can be found using the equation:

t = (Vf - Vi) / a

Substituting the values:

t = (0 - 112) / (-32)

t = 3.5 seconds

Therefore, the velocity at the maximum height is 0 ft/s.