Question

a 931 ml nacl solution is diluted to a volume of 1.34 l and a concentration of 2.00 m . what was the initial concentration?

Answer 1

To find the initial concentration of the NaCl solution, use the dilution formula: C1V1 = C2V2. Substituting the given values into the formula, the initial concentration is found to be 2.89 M.

Step-by-step explanation:

To find the initial concentration of the NaCl solution, we need to use the dilution formula:

C1V1 = C2V2

Where:

C1 = initial concentration

V1 = initial volume

C2 = final concentration

V2 = final volume

Given:

Initial volume, V1 = 931 ml = 0.931 L

Final volume, V2 = 1.34 L

Final concentration, C2 = 2.00 M

Substituting these values into the formula:

C1 x 0.931 L = 2.00 M x 1.34 L

Solving for C1:

C1 = (2.00 M x 1.34 L) / 0.931 L

C1 = 2.89 M

Therefore, the initial concentration of the NaCl solution was 2.89 M.