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determine the molairy of a solution formed by dissolving 568 mg of cai2 in enlough weater to yield 5 ml of oslution]drogen ion

User Tufekoi
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The molarity of the solution formed by dissolving 568 mg of CaI₂ in enough water to yield 55 mL of solution is 0.0345 M

How to calculate the molarity of the solution formed?

Lets begin by calculating the number of mole of CaI₂. This is shown below:

  • Mass of CaI₂ = 568 mg = 568 / 1000 = 0.568 g
  • Molar mass of CaI₂ = 293.8 g/mol
  • Mole of CaI₂ =?

Mole of CaI₂ = Mass of CaI₂ / molar mass of CaI₂

= 0.568 / 293.8

= 0.0019 mole

Now that we have the mole of CaI₂ in the solution, we shall calculate the molarity of the solution. This is shown below:

  • Mole of CaI₂ = 0.0019 mole
  • Volume of solution = 55 mL = 55 / 1000 = 0.055 L
  • Molarity of solution = ?

Molarity of solution = Mole of CaI₂ / volume of solution

= 0.0019 / 0.055

= 0.0345 M

Complete question:

Determine the molarity of a solution formed by dissolving 568 mg of CaI2 in enough water to yield 55.0 mL of solution.

User Nico Van Belle
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