The molarity of the solution formed by dissolving 568 mg of CaI₂ in enough water to yield 55 mL of solution is 0.0345 M
How to calculate the molarity of the solution formed?
Lets begin by calculating the number of mole of CaI₂. This is shown below:
- Mass of CaI₂ = 568 mg = 568 / 1000 = 0.568 g
- Molar mass of CaI₂ = 293.8 g/mol
- Mole of CaI₂ =?
Mole of CaI₂ = Mass of CaI₂ / molar mass of CaI₂
= 0.568 / 293.8
= 0.0019 mole
Now that we have the mole of CaI₂ in the solution, we shall calculate the molarity of the solution. This is shown below:
- Mole of CaI₂ = 0.0019 mole
- Volume of solution = 55 mL = 55 / 1000 = 0.055 L
- Molarity of solution = ?
Molarity of solution = Mole of CaI₂ / volume of solution
= 0.0019 / 0.055
= 0.0345 M
Complete question:
Determine the molarity of a solution formed by dissolving 568 mg of CaI2 in enough water to yield 55.0 mL of solution.