Question

50. (ii) the speed of waves on a string is . if the frequency of standing waves is 435 hz, how far apart are two adjacent nodes?

Answer 1

The boat bobs up and down on ocean waves 0.05 times per minute.

Step-by-step explanation:

Given:

Wave speed (v) = 2.00 m/s

Wavelength (λ) = 40.0 m

Propagation speed (c) = 5.00 m/s

Frequency (f) = ?

We can use the formula λ = v/f to find the frequency of the waves:

f = v/λ

Substituting the given values:

f = 2.00 m/s / 40.0 m = 0.05 Hz

Therefore, the boat bobs up and down on ocean waves 0.05 times per minute.