Question

how many millilitres of 5.0m copper (2) sulfate solution must be added to 160ml of h2o to achieve 0.30m copper 2 sulfate solution

Answer 1

Approximately 2666.67 millilitres (or 2.67 litres) of 5.0 M copper (II) sulfate solution must be added to 160 mL of water to achieve a 0.30 M copper (II) sulfate solution.

Step-by-step explanation:

To solve this problem, we can use the dilution formula:

C1V1 = C2V2

Here, C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given:

Initial volume (V1) = 160 mL

Desired final concentration (C2) = 0.30 M

We can rearrange the equation to find the required volume (V2) of 5.0 M copper (II) sulfate solution:

V2 = (C1 * V1) / C2

Substituting the given values:

V2 = (5.0 M * V1) / 0.30 M

Now, we can plug in the values and calculate:

V2 = (5.0 M * 160 mL) / 0.30 M = 2666.67 mL

Therefore, approximately 2666.67 millilitres (or 2.67 litres) of 5.0 M copper (II) sulfate solution must be added to 160 mL of water to achieve a 0.30 M copper (II) sulfate solution.