Final answer:
Using the quadratic formula in the given equation, the solutions are 1/2 and -1.
Step-by-step explanation:
To solve the equation 2x^2+x-4=0, we can use the quadratic formula.
The quadratic formula states that for an equation of the form ax^2+bx+c = 0, the solutions for x can be calculated using the formula:
x = (-b ± √(b^2-4ac)) / (2a)
For the given equation, a=2, b=1, and c=-4.
Plugging these values into the quadratic formula, we get:
x = (-1 ± √(1^2-4*2*(-4))) / (2*2)
This simplifies to:
x = (-1 ± √(9)) / 4
Therefore, the solutions for the equation are:
x = (-1 + 3) / 4
= 2/4
= 1/2
x = (-1 - 3) / 4
= -4/4
= -1.