Question

what is the velocity of the outer rim or a 12 cm diameter cd if the cd player spins the cd with a centripetal acceleration of 9 m/s^2

Answer 1

The velocity of the outer rim of the CD is 0.6 m/s.

Step-by-step explanation:

To find the velocity of the outer rim of the CD, we need to first calculate the centripetal acceleration using the formula:

a = v^2/r

where a is the centripetal acceleration, v is the velocity, and r is the radius. Rearranging the formula to solve for v, we have:

v = sqrt(a * r)

Given that the centripetal acceleration is 9 m/s^2 and the radius is half the diameter (which is 12 cm), we can substitute these values into the equation to find the velocity:

v = sqrt(9 * 0.12) = 0.6 m/s

Therefore, the velocity of the outer rim of the CD is 0.6 m/s.