The potential difference across the capacitor if the spacing between the plates is 1.10 mm is 216.67 V.
How to calculate the potential difference?
The capacitance of the capacitor is calculated as follows;
C = (εA)/d
where;
- A is the area of the plate
- d is the distance
A = 0.021 m x 0.021 m
A = 0.00041 m²
C = (8.85 x 10⁻¹² x 0.00041) / (0.0011 m)
C = 3.3 x 10⁻¹² F
The potential difference across the capacitor if the spacing between the plates is 1.10 mm is calculated as;
V = Q/C
V = (0.715 x 10⁻⁹) / ( 3.3 x 10⁻¹²)
V = 216.67 V
The complete question is below:
Two 2.10 cm x 2.10 cm plates that form a parallel plate capacitor are charged to 0.715 nC
what is the potential difference across the capacitor if the spacing between the plates is 1.10 mm ?